An algorithm generates numbers. Starting with the number 1, there is a N/(2N+1) chance that it will generate a new number, otherwise, it would generate an existing number with equal probability. Given that on the tenth move, a multiple of 3 is generated, what are the odds that on the 20th move, the number 8 would be the number generated?
A chessier one:
Given that a chess game is 69 moves long, what is the expected value of how far the white pieces moved?
one square diagonal = sqrt(2)
one knight hop = sqrt(5)
This one may require some advanced knowledge in mathematics:
find the value of \int_{0}^{1} logx/(x^5+1) dx
Enjoy solving it
Write a generalized function about the series of onestroke possible for regular polygons inscribed in other regular polygons using their midpoints as vertices. Define X as the number of polygons and Y as the sides of each polygon. Same path but different rotations/flips count as a different permutation.
Good luck :D
What is 1÷0?
there are 2 types of comments
genuine tormenting hell
or what is 9+10?
I'll start with the easy ones:
@End_Game_Flame said in #9:
> Whats 1+1?
2
@bixit00 said in #11:
> The person who solves this without a calculator wins
> 6875434922 / 217461
Above 31,600
@kayaKayabas said in #25:
> What is 1÷0?
Undefined. Not infinity. Common misconception, backfires in limits
Nah I think he gave up
@ForumMathSolver said in #6:
> Answer: (D) I and II only
>
> Explanation:
> We have:
> C = 5/9 (F - 32)
> or, F - 32 = C x 9/5
> or, F = 1.8C + 32
>
> Differentiating with respect to C (not required but just displaying lol)
> dF/dC = 1.8
> Thus, for a 1 degree rise in temperature in the Celsius scale, we have a 1.8 degree rise in temperature in the Fahrenheit scale.
>
> Conversely, dC/dF = 1/1.8
> or, dC/dF = 1/(9/5)
> or, dC/dF = 5/9
> Thus, for a 1 degree rise in temperature in the Fahrenheit scale, we have a 5/9 degree rise in temperature in the Celsius scale.
>
> Therefore, statements I and II are correct.
> Statement III is false because it obviously contradicts statement II.
>
> Alternate method (without calculus):
> Assume C' = C + 1, and F' = F + 1, assuming 1 degree increase in temperature of both scales, and then substitute both seperately into the equation, along with C and F, respectively.
> This method is simpler but longer.
you don't even need derivatives for this
common sense
or if you dont have that
just plug in 0 for C, increase C by 1, see what happens to F and do it for all 3 options.
or
if you don't have time
just use common sense
no way this is the hardest one
@Damkiller25 said in #8:
> @Samboy2023
> you wanna see my one of hardest problem in my exam in highschool?
> The base of the pyramid of the lattice ABCS is an equilateral triangular ABC with side length 6. On the lateral edges BS and CS are located points D and E, respectively, such that |BD | = |CE | and |DE | = 4 (see figure). The plane ADE is perpendicular to the plane of the lateral face BCS of the pyramid.
> img.zadania.info/zad/1199830/HzadT10x.gif
> have fun
>
> by the way, the link for exam with I took form
> zadania.info/d1771/96841
wait what's the question?@bixit00 said in #11:
> The person who solves this without a calculator wins
>
> 6875434922 / 217461
at least 9@limodet said in #23:
> This one may require some advanced knowledge in mathematics:
> find the value of \int_{0}^{1} logx/(x^5+1) dx
> Enjoy solving it
ok but wouldn't this be 0
the graph is below y=0 while 0 < x < 1 since log(x) when 0 < x < 1 is negative, and x^5+1 is positive when x>-1@PenguinWhack271828e said in #21:
> An algorithm generates numbers. Starting with the number 1, there is a N/(2N+1) chance that it will generate a new number, otherwise, it would generate an existing number with equal probability. Given that on the tenth move, a multiple of 3 is generated, what are the odds that on the 20th move, the number 8 would be the number generated?
i have no idea how to do this one
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