Simple SAT question:
If y^y is 4^1024, then what is y?
Simple SAT question:
If y^y is 4^1024, then what is y?
@ATREYAhyper said in #41:
4^1024 = 16^512 = 256^256
y = 256
@ATREYAhyper said in #41:
>
4^1024 = 16^512 = 256^256
y = 256
@ForumMathSolver
What is the Largest Prime Number found till now?
@ForumMathSolver
What is the Largest Prime Number found till now?
47354753468148625 X 53735471613 / 5343486436469 + 2762426854 -72434441242452=
YUP GOOD LUCK. YOU WILLL NEED IT.
ALSO DONT FORGET BODMAS!!
47354753468148625 X 53735471613 / 5343486436469 + 2762426854 -72434441242452=
YUP GOOD LUCK. YOU WILLL NEED IT.
ALSO DONT FORGET BODMAS!!
What is the maximum number of pieces I can have on the 8x8 chessboard such that none of them attack each other?
(Pieces, not including pawns)
(This is easy! Just think about it)
What is the maximum number of pieces I can have on the 8x8 chessboard such that none of them attack each other?
(Pieces, not including pawns)
(This is easy! Just think about it)
Here are different versions of the previous question:
- What if there must be at least one queen on the board?
- (Unrelated to 1) What if there had to be two rooks on the board?
- What if there were two adjacent rooks on the board?
- What if the king was on the hill?
- What if there were two opposite-colored bishops?
Here are different versions of the previous question:
1. What if there must be at least one queen on the board?
2. (Unrelated to 1) What if there had to be two rooks on the board?
3. What if there were two adjacent rooks on the board?
4. What if the king was on the hill?
5. What if there were two opposite-colored bishops?
The sum of the series 1 + 3 + 5^2+ 7 + 9^2+ ... upto 80 terms is
The sum of the series 1 + 3 + 5^2+ 7 + 9^2+ ... upto 80 terms is
@ajfang said in #18:
Took me about 5 minutes...
217461 x 10000 = 2174610000. (10000 x 217461)
2174610000 x 3 = 6523830000. (30000 x 217461)
6875434922 - 6523830000 = 351604922.
217461000 + 108730500 (217461000 divided by 2) = 326191500 (1500 x 217461)
351604922 - 326191500 = 25413422
217461 x 100 = 21746100 (100 x 217461)
25413422 - 21746100 = 3667322
2174610 + 1087305 = 3261915 (15 x 217461)
3667322 - 3261915 = 405407
217461 x 2 = 434922 (above 405407, so we can only put a 217461 here)
405407 - 217461 (1 x 217461) = 187946
30000 + 1500 + 100 + 15 + 1 = 31616 R 187946. And my answer...is 31,616 Remainder 187,946.
And after verifying with Google, I realized I was actually right... it gave me a decimal version (31,616.8642) instead of 31616 R 187946...but I don't care. Nice one @bixit00 !
it given me with calculator.net 3172.1147103...
@ajfang said in #18:
> Took me about 5 minutes...
> 217461 x 10000 = 2174610000. (10000 x 217461)
> 2174610000 x 3 = 6523830000. (30000 x 217461)
> 6875434922 - 6523830000 = 351604922.
> 217461000 + 108730500 (217461000 divided by 2) = 326191500 (1500 x 217461)
> 351604922 - 326191500 = 25413422
> 217461 x 100 = 21746100 (100 x 217461)
> 25413422 - 21746100 = 3667322
> 2174610 + 1087305 = 3261915 (15 x 217461)
> 3667322 - 3261915 = 405407
> 217461 x 2 = 434922 (above 405407, so we can only put a 217461 here)
> 405407 - 217461 (1 x 217461) = 187946
>
> 30000 + 1500 + 100 + 15 + 1 = 31616 R 187946. And my answer...is 31,616 Remainder 187,946.
>
> And after verifying with Google, I realized I was actually right... it gave me a decimal version (31,616.8642) instead of 31616 R 187946...but I don't care. Nice one @bixit00 !
it given me with calculator.net 3172.1147103...
@Damkiller25 said in #8:
@Samboy2023
you wanna see my one of hardest problem in my exam in highschool?
The base of the pyramid of the lattice ABCS is an equilateral triangular ABC with side length 6. On the lateral edges BS and CS are located points D and E, respectively, such that |BD | = |CE | and |DE | = 4 (see figure). The plane ADE is perpendicular to the plane of the lateral face BCS of the pyramid.
img.zadania.info/zad/1199830/HzadT10x.gif
have fun
by the way, the link for exam with I took form
zadania.info/d1771/96841
its (idk language) i dont comprend
@Damkiller25 said in #8:
> @Samboy2023
> you wanna see my one of hardest problem in my exam in highschool?
> The base of the pyramid of the lattice ABCS is an equilateral triangular ABC with side length 6. On the lateral edges BS and CS are located points D and E, respectively, such that |BD | = |CE | and |DE | = 4 (see figure). The plane ADE is perpendicular to the plane of the lateral face BCS of the pyramid.
> img.zadania.info/zad/1199830/HzadT10x.gif
> have fun
>
> by the way, the link for exam with I took form
> zadania.info/d1771/96841
its (idk language) i dont comprend
whats ghe maximum en passent that are possible in one game?
whats ghe maximum en passent that are possible in one game?