@bixit00 said in #10:
>
The person who solves this without a calculator wins
6875434922 / 217461
I think I will turn insane form bullshit math problems.
Please prove that integers below 1000 are consistent with the Collatz conjecture.
@Samboy2023 said in #2:
> C=5/9(F-32)
>
> The equation above shows how temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured in degrees Celsius. Based on the equation, which of the following must be true?
>
> 1. A temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of 5/9 degree Celsius.
> 2. A temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit.
> 3. A temperature increase of 5/9 degree Fahrenheit is equivalent to a temperature increase of 1 degree Celsius.
>
> A) I only
> B) II only
> C) III only
> D) I and II only
Even I didnt know what the answer was bruh
Answer: (D) I and II only
Explanation:
We have:
C = 5/9 (F - 32)
or, F - 32 = C x 9/5
or, F = 1.8C + 32
Differentiating with respect to C (not required but just displaying lol)
dF/dC = 1.8
Thus, for a 1 degree rise in temperature in the Celsius scale, we have a 1.8 degree rise in temperature in the Fahrenheit scale.
Conversely, dC/dF = 1/1.8
or, dC/dF = 1/(9/5)
or, dC/dF = 5/9
Thus, for a 1 degree rise in temperature in the Fahrenheit scale, we have a 5/9 degree rise in temperature in the Celsius scale.
Therefore, statements I and II are correct.
Statement III is false because it obviously contradicts statement II.
Alternate method (without calculus):
Assume C' = C + 1, and F' = F + 1, assuming 1 degree increase in temperature of both scales, and then substitute both seperately into the equation, along with C and F, respectively.
This method is simpler but longer.
This is the answer given by him AKA @ForumMathSolver
Here's a pretty easy one to get you warmed up. Either prove or find a counterexample for:
Every even natural number greater than 2 is the sum of two prime numbers.
Answer to #13
Berechnungen mit Computern ergaben:
Alle positiven ganzen Zahlen bis 2^68 als Startwerte bestätigen die Vermutung (Stand Juli 2020).
1000 < 2^68
Quod erat demonstrandum?
@bixit00 said in #11:
> The person who solves this without a calculator wins
>
> 6875434922 / 217461
Took me about 5 minutes...
217461 x 10000 = 2174610000. (10000 x 217461)
2174610000 x 3 = 6523830000. (30000 x 217461)
6875434922 - 6523830000 = 351604922.
217461000 + 108730500 (217461000 divided by 2) = 326191500 (1500 x 217461)
351604922 - 326191500 = 25413422
217461 x 100 = 21746100 (100 x 217461)
25413422 - 21746100 = 3667322
2174610 + 1087305 = 3261915 (15 x 217461)
3667322 - 3261915 = 405407
217461 x 2 = 434922 (above 405407, so we can only put a 217461 here)
405407 - 217461 (1 x 217461) = 187946
30000 + 1500 + 100 + 15 + 1 = 31616 R 187946. And my answer...is 31,616 Remainder 187,946.
And after verifying with Google, I realized I was actually right... it gave me a decimal version (31,616.8642) instead of 31616 R 187946...but I don't care. Nice one @bixit00 !
@ajfang said in #18:
>
Bro, you literally made that, LOL
@End_Game_Flame said in #9:
> Whats 1+1?
After hours of solving, I finally discovered 1+1=3
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