@AsDaGo said in #27:
> Because e isn't a word, it's a letter. In fact, neither is y!
it's a number. e is a word of a name of a number commonly calledd e aka e the number.
e^pi×i-1=0
must I remind you?
Doesn't that start with 2 and never end?
@WassimBerbar said in #30:
> In a city, there were two barbers:
> 1st barber is good, he acomplishes good haircuts for affordable prices.
> 2nd barber is bad, he fails haircuts for exorbitant prices.
> One time, someone in the city wanted a haircut, but he went to the bad barber. Who and why?
It was the first barber, because he'd never learned how to cut his own hair.
yes, @Passionate_Player
@igmo_fitzpatzer said in #31:
> it's a number. e is a word of a name of a number commonly calledd e aka e the number.
>
> e^pi×i-1=0
>
> must I remind you?
it's e^(i*π) + 1 = 0
not -
aloha, @WassimBerbar
@igmo_fitzpatzer said in #31:
> it's a number. e is a word of a name of a number commonly calledd e aka e the number.
>
> e^pi×i-1=0
>
> must I remind you?
Oh yeah, that is true, though your equation isn't quite right. The left side of your equation is approximately equal to 23.141 i - 1, not 0. What you probably meant to write, e^(pi*i) - 1, is equal to -2, not 0. Actually, e^(pi*i) + 1 = 0.
@AsDaGo said in #37:
> Oh yeah, that is true, though your equation isn't quite right. The left side of your equation is approximately equal to 23.141 i - 1, not 0. What you probably meant to write, e^(pi*i) - 1, is equal to -2, not 0. Actually, e^(pi*i) + 1 = 0.
Yes, Thank you, AsDaGo. Silly me always touting my great big ignorance as concisely asdago I can superfluous.
Umm it is a cool math tho ain't'n it. Further still it satisfies the riddle oh but not fun in the way.
@WassimBerbar, aloha
I am a star but you won't get far
When I'm gone my legacy is strong
all that seek me
woo am i?
> I am a star but you won't get far
> When I'm gone my legacy is strong
> all that seek me
>
> woo am i?
dad?
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