No
Non
No
Nein
No
#7
is clever lol
https://youtu.be/zIV4poUZAQo?feature=shared
Which word is longer:
A. long
B. lengthiest
You say, "B. stretchier"
no no no ...
@CSKA_Moscou said in #13:
>
Knights of No: We are the Knights who scream, "NOOO!!" And we demand a sacrifice!
The Knights of Monty Python: What type of sacrifice?
Knights of No: Find us...a strawberry. Or we...will scream "NOOOOO!!"
*after finding strawberry (note: not shrubbery)*
Knights of Eeek Eeek Eeek Eeek Ptartang Zoo Poing: We are NOW the Knights who scream, "EEEEEEEEEEEEEEEEEEEEEEK EEEEEEEEEEEEEEEEEEK EEEEEEEEEEEEEK EEEEEEEEEEEEK Ptartang ZOOOOOOOOOOOOOOOOOOOOOOO Pooooing!" And we demand a sacrifice!!
Knights of Monty Python: Knights who until recently screamed "NOOOOOO!!" what type of sacrifice?
Knights of Eeek Eeek Eeek Eeek Ptartang Zoo Poing: And now...you must cut the shortest STONE in the forest...
WITH A SALMON!!
Knights of Monty Python: It can't be done!
Knights of Eeek Eeek Eeek Eeek Ptartang Zoo Poing: *suddenly all duck and shield themselves* NOOOOO!!! AHHHHHHH!!
*mind you, moose bites can be pretty nasty*
Conventionally comedy movies are barely funny at all, while this one ensures that you die of laughter before it ends.
I would be honored to be included in your block list!
no
never
nae
negative
nope
nah
naw
nay
No
Nulla
None
Nope
Nein
Нет
不
いいえ
@coltsare1 said in #6:
> Theorem: no = yes Proof: Assume no = \(x\) and yes = \(y\).Define know such that \(x=-\text{know}\) and \(y=\frac{1}{\text{know}}\).Set the variables equal to each other: \(x=y\).Substitute the definitions: \(-\text{know}=\frac{1}{\text{know}}\).Multiply both sides by know: \(-\text{know}^{2}=1\).Multiply both sides by -1: \(\text{know}^{2}=-1\).Take the square root of both sides: \(\text{know}=\sqrt{-1}=i\).Substitute know back into the definition for \(x\): \(x=-i\).Substitute know back into the definition for \(y\): \(y=\frac{1}{i}\).Simplify \(y\) by multiplying the numerator and denominator by \(i\): \(y=\frac{1}{i}\times \frac{i}{i}=\frac{i}{i^{2}}=\frac{i}{-1}=-i\).Since \(x=-i\) and \(y=-i\), we can conclude that \(x=y\).Therefore, no = yes.
NOOOOOOOOOOOOOOOOOOO
does yesn't count as no?
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