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we can only say 'no' in this chat if you say other things, I will block you

no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no

no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no

no no no no no no no no no no no no no no no no no no no

no no no no no no no no no no no no no no no no no no no

Theorem: no = yes Proof: Assume no = \(x\) and yes = \(y\).Define know such that \(x=-\text{know}\) and \(y=\frac{1}{\text{know}}\).Set the variables equal to each other: \(x=y\).Substitute the definitions: \(-\text{know}=\frac{1}{\text{know}}\).Multiply both sides by know: \(-\text{know}^{2}=1\).Multiply both sides by -1: \(\text{know}^{2}=-1\).Take the square root of both sides: \(\text{know}=\sqrt{-1}=i\).Substitute know back into the definition for \(x\): \(x=-i\).Substitute know back into the definition for \(y\): \(y=\frac{1}{i}\).Simplify \(y\) by multiplying the numerator and denominator by \(i\): \(y=\frac{1}{i}\times \frac{i}{i}=\frac{i}{i^{2}}=\frac{i}{-1}=-i\).Since \(x=-i\) and \(y=-i\), we can conclude that \(x=y\).Therefore, no = yes.

Theorem: no = yes Proof: Assume no = \(x\) and yes = \(y\).Define know such that \(x=-\text{know}\) and \(y=\frac{1}{\text{know}}\).Set the variables equal to each other: \(x=y\).Substitute the definitions: \(-\text{know}=\frac{1}{\text{know}}\).Multiply both sides by know: \(-\text{know}^{2}=1\).Multiply both sides by -1: \(\text{know}^{2}=-1\).Take the square root of both sides: \(\text{know}=\sqrt{-1}=i\).Substitute know back into the definition for \(x\): \(x=-i\).Substitute know back into the definition for \(y\): \(y=\frac{1}{i}\).Simplify \(y\) by multiplying the numerator and denominator by \(i\): \(y=\frac{1}{i}\times \frac{i}{i}=\frac{i}{i^{2}}=\frac{i}{-1}=-i\).Since \(x=-i\) and \(y=-i\), we can conclude that \(x=y\).Therefore, no = yes.

NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO FLAPS IS DUMB NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO

NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO FLAPS IS DUMB NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO

noooooooooooooooooooooooooooooooooooooooooooo

noooooooooooooooooooooooooooooooooooooooooooo

yes.
yes!
yes?
yes..?
yes :/
yes :)
yes.. :(
yes :D

yes. yes! yes? yes..? yes :/ yes :) yes.. :( yes :D

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