no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no
no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no no
no no no no no no no no no no no no no no no no no no no
no no no no no no no no no no no no no no no no no no no
nice way to greet people!
nice way to greet people!
not really
Yes
Theorem: no = yes Proof: Assume no = \(x\) and yes = \(y\).Define know such that \(x=-\text{know}\) and \(y=\frac{1}{\text{know}}\).Set the variables equal to each other: \(x=y\).Substitute the definitions: \(-\text{know}=\frac{1}{\text{know}}\).Multiply both sides by know: \(-\text{know}^{2}=1\).Multiply both sides by -1: \(\text{know}^{2}=-1\).Take the square root of both sides: \(\text{know}=\sqrt{-1}=i\).Substitute know back into the definition for \(x\): \(x=-i\).Substitute know back into the definition for \(y\): \(y=\frac{1}{i}\).Simplify \(y\) by multiplying the numerator and denominator by \(i\): \(y=\frac{1}{i}\times \frac{i}{i}=\frac{i}{i^{2}}=\frac{i}{-1}=-i\).Since \(x=-i\) and \(y=-i\), we can conclude that \(x=y\).Therefore, no = yes.
Theorem: no = yes Proof: Assume no = \(x\) and yes = \(y\).Define know such that \(x=-\text{know}\) and \(y=\frac{1}{\text{know}}\).Set the variables equal to each other: \(x=y\).Substitute the definitions: \(-\text{know}=\frac{1}{\text{know}}\).Multiply both sides by know: \(-\text{know}^{2}=1\).Multiply both sides by -1: \(\text{know}^{2}=-1\).Take the square root of both sides: \(\text{know}=\sqrt{-1}=i\).Substitute know back into the definition for \(x\): \(x=-i\).Substitute know back into the definition for \(y\): \(y=\frac{1}{i}\).Simplify \(y\) by multiplying the numerator and denominator by \(i\): \(y=\frac{1}{i}\times \frac{i}{i}=\frac{i}{i^{2}}=\frac{i}{-1}=-i\).Since \(x=-i\) and \(y=-i\), we can conclude that \(x=y\).Therefore, no = yes.
NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO FLAPS IS DUMB NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO
NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO FLAPS IS DUMB NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO NO
noooooooooooooooooooooooooooooooooooooooooooo
noooooooooooooooooooooooooooooooooooooooooooo
yes.
yes!
yes?
yes..?
yes :/
yes :)
yes.. :(
yes :D
yes.
yes!
yes?
yes..?
yes :/
yes :)
yes.. :(
yes :D
Maybe...