<Comment deleted by user>
<Comment deleted by user>
Problem: if 11987 + 21986 + 3*1985 + ... + 1986 * 2 + 1987 * 1 = 1987 * 994 * x, then what is x?
Problem: if 1*1987 + 2*1986 + 3*1985 + ... + 1986 * 2 + 1987 * 1 = 1987 * 994 * x, then what is x?
What is the sum of the infinite series 1/(2^2) + 2/(3^3) + 3/(4^4) +4/(5^5) + 5/(6^6)...? I don't know the answer at all lol
What is the sum of the infinite series 1/(2^2) + 2/(3^3) + 3/(4^4) +4/(5^5) + 5/(6^6)...? I don't know the answer at all lol
2+2=?
2+2=?
A block weighs half a block plus 100.
How much does a block weighs
A block weighs half a block plus 100.
How much does a block weighs
<Comment deleted by user>
What is the sum of the infinite series 1/(2^2) + 2/(3^3) + 3/(4^4) +4/(5^5) + 5/(6^6)...?
- It is infinite
Sum (k-1)/k^2 = Sum (1/k - 1/k^2) = Sum (1/k) - Sum (1/k^2) = Zeta(1) - Zeta(2) = infinite - finite = infinite
What is the sum of the infinite series 1/(2^2) + 2/(3^3) + 3/(4^4) +4/(5^5) + 5/(6^6)...?
* It is infinite
Sum (k-1)/k^2 = Sum (1/k - 1/k^2) = Sum (1/k) - Sum (1/k^2) = Zeta(1) - Zeta(2) = infinite - finite = infinite
@tpr said in #18:
What is the sum of the infinite series 1/(2^2) + 2/(3^3) + 3/(4^4) +4/(5^5) + 5/(6^6)...?
- It is infinite
Sum (k-1)/k2 = Sum (1/k - 1/k2) = Sum (1/k) - Sum (1/k2) = infinite - finite = infinite
I suppose that the sign "^" in #14 meant exponentiation. The series sum_{n=1}^{infinity} n/((n+1)^(n+1)) is convergent.
@tpr said in #18:
> What is the sum of the infinite series 1/(2^2) + 2/(3^3) + 3/(4^4) +4/(5^5) + 5/(6^6)...?
> * It is infinite
> Sum (k-1)/k2 = Sum (1/k - 1/k2) = Sum (1/k) - Sum (1/k2) = infinite - finite = infinite
I suppose that the sign "^" in #14 meant exponentiation. The series sum_{n=1}^{infinity} n/((n+1)^(n+1)) is convergent.
"I suppose"
- I put in 2 uppercase 2, but this site renders it as plain 2
I edited above.
The series is divergent.
"I suppose"
* I put in 2 uppercase 2, but this site renders it as plain 2
I edited above.
The series is divergent.
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