#1
For a scientific twist:
If F(t) is the number of frogs at time t, S(t) is the number of snakes at time t, E(t) is the number of eagles at time t, then the pair of differential equations
dS(t)/dt = a F(t)
dE(t)/dt = b S(t)
where a and b are constants
allows to calculate the numbers of eagles and snakes over time
#1
For a scientific twist:
If F(t) is the number of frogs at time t, S(t) is the number of snakes at time t, E(t) is the number of eagles at time t, then the pair of differential equations
dS(t)/dt = a F(t)
dE(t)/dt = b S(t)
where a and b are constants
allows to calculate the numbers of eagles and snakes over time
#12
d = differential
dS(t)/dt = limit for t2 -> t1 of (S(t2) - S(t1))/(t2 - t1)
#12
d = differential
dS(t)/dt = limit for t2 -> t1 of (S(t2) - S(t1))/(t2 - t1)
Eagles won't suffer. They will eat snakes instead. And by the way, which hunter hunts frogs?
Eagles won't suffer. They will eat snakes instead. And by the way, which hunter hunts frogs?
#14
If half of the frogs die for example because people want to eat frog legs, then half of the snakes will starve to death for lack of frogs and then half of the eagles will starve to death for lack of snakes.
#14
If half of the frogs die for example because people want to eat frog legs, then half of the snakes will starve to death for lack of frogs and then half of the eagles will starve to death for lack of snakes.
I learnt about it in year 4
I learnt about it in year 4
Here is some more science about this
https://en.wikipedia.org/wiki/Lotka%E2%80%93Volterra_equations