Any way to check average move time in a game? • page 1/1 • Lichess Feedback • lichess.org

There is a way to check average move time overall in the insights but is there any way to check the average move time in the opening, middlegame and endgame of one single game? Atleast a total time by one side will work as the total time taken is not so clear in games with increments.

Autofill

Divide total time taken by amount of moves

RudraveerM

@Autofill said in #2:

Divide total time taken by amount of moves
How to get the total time taken in games with increments?

@Autofill said in #2: > Divide total time taken by amount of moves How to get the total time taken in games with increments?

Autofill

@RudraveerM said in #3:

How to get the total time taken in games with increments?
Add increment amount to your total

@RudraveerM said in #3: > How to get the total time taken in games with increments? Add increment amount to your total

Dukedog edited

Move times in analysis should give you the info you're after. You will have to reduce it to averages.

RudraveerM

@Autofill said in #4:

Add increment amount to your total
That works for the whole game but not just for the opening middlegame or endgame

@Autofill said in #4: > Add increment amount to your total That works for the whole game but not just for the opening middlegame or endgame

Autofill

@RudraveerM said in #6:

That works for the whole game but not just for the opening middlegame or endgame
It works for parts of the games too

@RudraveerM said in #6: > That works for the whole game but not just for the opening middlegame or endgame It works for parts of the games too

SigurdSigurdsson

To summarize above posts, the formula should be something like this (Note, that you need to use the same unit, e.g. [s], for all variables):

Average time per move ≈ (T_1 - T_2) / N + I
where:
T_1 is starting time,
T_2 is end time,
N is number of moves between T_1 and T_2,
I is increment.

E.g.: T_1 = 5 [min] = 300 [s]
T_2 = 2 [min] = 120 [s]
N = 45
I = 3 [s]
Average time per move ≈ (T_1 - T_2) / N + I = (300 - 120) / 45 + 3
Average time per move ≈ 7 [s]

Note that in order to get the exact number for the case of T_1 being beginning of the game, the formula would be slightly more complicated, because your first move does cost 0 [s] and give you no bonus for the increment. That's the reason I used "≈" instead of "=". I could derive the exact formula for that case, but I don't want to turn this post into math lecture. Also I am engineer, so in this case I would value practicality and simplicity over exactness (in another words, I am a little bit lazy).

Ok, ok, I lied, here is the formula for T_1 being the beginning of the game:
Average time per move = (T_1 - T_2) / (N - 1) + I * (N - 1) / N

To summarize above posts, the formula should be something like this (Note, that you need to use the same unit, e.g. [s], for all variables): Average time per move ≈ (T_1 - T_2) / N + I where: T_1 is starting time, T_2 is end time, N is number of moves between T_1 and T_2, I is increment. E.g.: T_1 = 5 [min] = 300 [s] T_2 = 2 [min] = 120 [s] N = 45 I = 3 [s] Average time per move ≈ (T_1 - T_2) / N + I = (300 - 120) / 45 + 3 Average time per move ≈ 7 [s] Note that in order to get the exact number for the case of T_1 being beginning of the game, the formula would be slightly more complicated, because your first move does cost 0 [s] and give you no bonus for the increment. That's the reason I used "≈" instead of "=". I could derive the exact formula for that case, but I don't want to turn this post into math lecture. Also I am engineer, so in this case I would value practicality and simplicity over exactness (in another words, I am a little bit lazy). Ok, ok, I lied, here is the formula for T_1 being the beginning of the game: Average time per move = (T_1 - T_2) / (N - 1) + I * (N - 1) / N