Search "user:ChessMathNerd"

@polylogarithmique you can actually make that a log(3) because you can split into groups of 17, 17, 16, weigh the two 17's, then split one into groups of 6, 6, 5, etc, and do it slightly faster that w…

@wornaki Also, I am guessing that you tend to lose more commonly against players who, in your words, do not play sanely. If that is the case, avoiding such players could potentially raise your rating …

@wornaki I know I say this every time you make a post about disliking unsound openings, but I'll say it again, for all those serious players out there. Never, ever, try to avoid bad openings by your o…

@Nomen-Nonatur #46, so more rigorously: Form the t meters of material into 2(pi)t/(t+1) degrees of a circle, and then insert the last meter of material to form a new circle with t+1 meters of material…

@Nomen-Nonatur So, as a mathematician, your previous comments have gotten me thinking about more exact ways to measure the expansion of the circle. There are two ways that I have been thinking. The fi…

@InkyDarkBird That doesn't work because as the circle expands, the robot is dragged forwards depending on where it is on the circle. The speed of the robot is slightly faster than .5. A correct soluti…

@polylogarithmique So actually as I think about this more, my switch to a straight line has a small issue. The drag placed on the robot is greatest at the 1/2 way mark, and it decreases thereafter, wh…

@polylogarithmique Its a/(1+t) sorry, just a basic proportion. Also, yeah I meant quadratic my bad.

@TakeThePawnOrLose : I have been away from differential calculus for a long time, but here is my best shot. The answer is yes, the robot will reach the end, and is capable of encircling the rubber ban…