Only engines or top grandmasters can get acpl (average centipawn loss) less than 5. It is the measure of how the moves played. In a position there can be 100 of good moves, and if you play the BEST move in each position you may get centipawn loss 0.
its possible to have a acpl of 0 even for both players. see this game
But only like this i guess since the computer find it to tough to handle this position ofcourse if someone blunders it should give one not a acpl off 0
But it thinks white is winning in the start i honestly prefer white( white willnot promote but black is more exposed and a4 h4 d4 e4 ideas seems good i notice from videos in such positions many don't understand the position well that people underestimate the power of the bishops.)
But +99 is def not right but basicly the thing is that a computer not made to analyse some positions because obviously there where some blunders made so technical a 0acpl can be played esp from a position like this.
But in a standard game of chess it seems unlikely to get a acpl of 0 a low acpl very low is also good possible if a game takes really long and if its just are many trades when the difficulty factor is low (but surely not a acpl of 0 i guess.)
if one got a low acpl it don't always mean its a achievement if one got a low acpl and the difficulty factor is high than its actually a achievement .
But its not a achievement if one simply take all the free pieces or play a endgame out of uneven bishops for +100 moves that lowers the acpl by quite a bit.
Just trying to explain how acpl works imo. and that a low acpl don't always ness mean its like a achievement but in some cases it actuallly is 🙂
But only like this i guess since the computer find it to tough to handle this position ofcourse if someone blunders it should give one not a acpl off 0
But it thinks white is winning in the start i honestly prefer white( white willnot promote but black is more exposed and a4 h4 d4 e4 ideas seems good i notice from videos in such positions many don't understand the position well that people underestimate the power of the bishops.)
But +99 is def not right but basicly the thing is that a computer not made to analyse some positions because obviously there where some blunders made so technical a 0acpl can be played esp from a position like this.
But in a standard game of chess it seems unlikely to get a acpl of 0 a low acpl very low is also good possible if a game takes really long and if its just are many trades when the difficulty factor is low (but surely not a acpl of 0 i guess.)
if one got a low acpl it don't always mean its a achievement if one got a low acpl and the difficulty factor is high than its actually a achievement .
But its not a achievement if one simply take all the free pieces or play a endgame out of uneven bishops for +100 moves that lowers the acpl by quite a bit.
Just trying to explain how acpl works imo. and that a low acpl don't always ness mean its like a achievement but in some cases it actuallly is 🙂
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This is likely the most perfect ultrabullet game that exists 1 ACPL lichess.org/gwi6BpTg
#1, nothing's impossible
my inner thoughts: what is this acpl? is it "a chess premier league?"
my inner thoughts: what is this acpl? is it "a chess premier league?"
its certainly possible because i somehow did it once: lichess.org/xNLGDBDU/black#0
Ok, where is my prize?
@mrbumba1287
pffft 1 inaccuracy. You should learn to play good like me 0 0 0 0 :))))))
pffft 1 inaccuracy. You should learn to play good like me 0 0 0 0 :))))))
@AnantKalia2006 said in #1:
> Hi guys,
> recently I have been thinking about if there is anyone who ever had an 0 ACPL in one game. I even analyzed a Stockfish 14 game against Leela and it showed an ACPL of 2, and not 0. How is 0 ACPL even possible?
0 ACPL is easy. Its easy in Antichess games.
Proof:
> Hi guys,
> recently I have been thinking about if there is anyone who ever had an 0 ACPL in one game. I even analyzed a Stockfish 14 game against Leela and it showed an ACPL of 2, and not 0. How is 0 ACPL even possible?
0 ACPL is easy. Its easy in Antichess games.
Proof:
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