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Instead of waiting a billion hours for the answers of my math questions to be answered, has anyone ever heard of "calculator"? Or maybe if you don't have one, a "Brain"? :)

P.S, This was just a lighthearted joke, so don't be offended by it! LOL! :)
Edit: Thanks for understanding my sense of humor! :)

Instead of waiting a billion hours for the answers of my math questions to be answered, has anyone ever heard of "calculator"? Or maybe if you don't have one, a "Brain"? :) P.S, This was just a lighthearted joke, so don't be offended by it! LOL! :) Edit: Thanks for understanding my sense of humor! :)

@Mishi2306 said in #22:

Instead of waiting a billion hours for the answers of my math questions to be answered, has anyone ever heard of "calculator"? Or maybe if you don't have one, a "Brain"? :)

P.S, This was just a lighthearted joke, so don't be offended by it! LOL! :)
well it was funny

@Mishi2306 said in #22: > Instead of waiting a billion hours for the answers of my math questions to be answered, has anyone ever heard of "calculator"? Or maybe if you don't have one, a "Brain"? :) > > P.S, This was just a lighthearted joke, so don't be offended by it! LOL! :) well it was funny

@imminentloss-foryou said in #20:

For which value of k is √2016 + √56 equal to 14^k?
(Assuming k is a real number)
√2016 + √56 = 14^k
Thus, √(36*56) + √56 = 14^k
Thus, √36 * √56 + √56 = 14^k
Thus, 6√56 + √56 = 14^k
Thus, 7√56 = 14^k
Thus, 7√(14 x 4) = 14^k
Thus, 7(√14 * √4) = 14^k
Thus, 14√14 = 14^k
Thus, 14^(3/2) = 14^k
Taking logarithms of both sides (k is a real number)
k log 14 = (3/2) log 14
Since log 14 isn't equal to 0, thus:
k = 3/2

Or you could have taken logarithms at the first step itself and then worked on.

@imminentloss-foryou said in #20: > For which value of k is √2016 + √56 equal to 14^k? (Assuming k is a real number) √2016 + √56 = 14^k Thus, √(36*56) + √56 = 14^k Thus, √36 * √56 + √56 = 14^k Thus, 6√56 + √56 = 14^k Thus, 7√56 = 14^k Thus, 7√(14 x 4) = 14^k Thus, 7(√14 * √4) = 14^k Thus, 14√14 = 14^k Thus, 14^(3/2) = 14^k Taking logarithms of both sides (k is a real number) k log 14 = (3/2) log 14 Since log 14 isn't equal to 0, thus: k = 3/2 Or you could have taken logarithms at the first step itself and then worked on.

@teachmewell said in #18:

Sure.
Can you see this?
imgur.com/a/toAlAyT
We have an outer black triangle, with given sidelengths and given area (purple). In the middle of the longest side is the start of another triangle, whose angle equals one of the bigger black triangle (blue angle). Area of purple = area yellow * 4
Just to clarify, the lines joining X to the two sides are such that the angle formed between them is alpha, right? In other word, there are other such lines possible, right?

@teachmewell said in #18: > Sure. > Can you see this? > imgur.com/a/toAlAyT > We have an outer black triangle, with given sidelengths and given area (purple). In the middle of the longest side is the start of another triangle, whose angle equals one of the bigger black triangle (blue angle). Area of purple = area yellow * 4 Just to clarify, the lines joining X to the two sides are such that the angle formed between them is alpha, right? In other word, there are other such lines possible, right?

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