Can you win with one queen against 4 pawns? [difficult]

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Tried but i stalemated the game

yes it is tooo hard but i will tried to win or stalemate

1. Qf2 is obvious, but 2. Kc8 - I have no idea how one can find it without looking in the tablebase.

#13
The winning method is largely the same as if only pawn e2 were there: with checks and pins force the king to the promotion square and then rapproach the king. The king must march along the light squares, so as to not obstruct the queen checks on dark squares. That explains 2 Kc8.

Yeah, I get that, but you have Kd7 and Kc6. There's very specific sequence of checks involving triangulation, you should make an approching king move only when your queen is on f4, stopping the h pawn. Not quite obvious that you need the whole d-file to reach that (this is why Kd7 doesn't work). Why Kc6 doesn't work I'm not so sure though.

#15 After Kc6 the queen can no longer go to c7 as it would be in the shadow of Kc6.

Uh, why wouldn't the queen be able to go to c7? I don't get it.

The queen must go to c7 to keep an eye on h2. If black can advance h2, then he holds the draw. If the queen goes to c7 with the king on c6, then the queen has no longer activity along the c-file. So the king must approach the passed pawn at e2 in a roundabout way along light squares that does not interfere with the activity of the queen. Thus Kc8-b7-a6-b5-a4-b3-c2-d3

I see all that, but why does the queen need the activity over the c-file? Isn't the b8-h2 diagonal enough? Where is the c-file used in the winning sequence? How is it important?

1 Qf2 Kd2 2 Kc8! Kd1 3 Qd4+ Ke1 4 Qe5 Kd1 5 Qa1+ Kd2 6 Qa5+ Kd1 7 Qd8+ Ke1 8 Qc7 holds h3

1 Qf2 Kd2 2 Kc6? Kd1 3 Qd4+ Ke1 4 Qe5 Kd1 5 Qa1+ Kd2 6 Qa5+ Kd1 7 Qd8+ Kc1 and Qc7 does not work as Kc6 stands in the way