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Please explain this puzzle

Knight (3) and bishop (3) together are conisdered to be more valueable than a rook (5). I think it depends on the situation on the board and on the activity of the pieces but in most cases the puzzles are wortking with this rule.
Yes, it is: Use the following table for a (rough) estimate of the value of pieces:

Queen: 9 units
Rook: 5 units
Knight/bishop: 3 units
Pawn: 1 unit

If you change the rook (5 units) for a knight and a bishop (6 units) it is clearly a gain.

Notice, that these values aren't set in stone: depending on the actual position the value of a certain piece may increase or decrease. I.e. in a certain situation a knight may win while a queen will not, so it might make sense to sacrifice the queen just to make room for the knight. But in the "average" position this table reflects about the values well.

Common modifications to the above table:
Usually bishops are slightly more valuable than knights so bishops may be valued 3.5. (Or, to put it differently, positions which favour the bishops are more common than positions favouring the knights.)

Also the pair of bishops is worth slightly more than 2 bishops on themselves. This also depends on the positions but is usually true.

Notice that more pieces can exert more force than less pieces, even if of the same value: i.e. three light pieces are about the same as one queen but they can attack another piece three times while the queen is only able to defend it once. The same goes for i.e. rook vs. two light pieces, queen vs. two rooks, etc.

krasnaya
is it really worth it to sack the rook for a knight and bishop?
Yes, is good trade, take two pieces with great movility. Lost the tower, but is two agains one
It's a very easy puzzle. You gane Bishop and Knight for a Rook and the final position is easielly winning for the White

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