Can you win with 5 knights against a queen

In a hypothetical endgame where it'd king and 5 knights vs king and queen, can the side with knights win and how?

If someone wants to give it a try:
lichess.org/analysis/standard/8/8/3q4/3k4/8/1N1K1N1N/8/3N1N2_w_-_-

Start by sacrificing one of the knights. 4 knights against a queen is a tablebase win.

here is a stockfish solution:
[Site "ff0-desktop"]
[Date "2019.04.13"]
[Round "-"]
[White "Stockfish 310318 64 POPCNT"]
[Black "Stockfish 310318 64 POPCNT"]
[Result "1-0"]
[TimeControl "40/120"]
[FEN "8/8/3q4/3k4/8/1N1K1N1N/8/3N1N2 w - - 0 1"]
[SetUp "1"]

{--------------
. . . . . . . .
. . . . . . . .
. . . q . . . .
. . . k . . . .
. . . . . . . .
. N . K . N . N
. . . . . . . .
. . . N . N . .
white to play
--------------}
1. Nfe3+ {+7,85/19} Kc6+ {-8,35/18 2,7} 2. Nbd4+ {+7,60/20 1,5} Kc5
{-10,10/23 9} 3. Nc3 {+10,05/19 1,0} Qa6+ {-13,35/26 10} 4. Ncb5
{+10,25/20 1,0} Qg6+ {-99,50/23 4} 5. Ke2 {+10,25/23 0,7} Qh6
{-99,34/22 2,0} 6. Nhg5 {+16,62/22 1,3} Kb4 {-99,62/29 1,9} 7. Ne4
{+99,51/23 0,4} Ka5 {-99,72/26 0,5} 8. Nd5 {+99,61/28 0,7} Qh3
{-99,76/32 1,8} 9. Nbd6 {+99,81/32 0,7} Qg2+ {-99,88/37 0,5} 10. Kd3
{+99,83/38 0,8} Qf1+ {-99,88/44 0,6} 11. Kc2 {+99,85/43 0,8} Qe2+
{-99,90/49 0,7} 12. Nxe2 {+99,91/56 0,7} Ka4 {-99,92/74 0,6} 13. Ned4
{+99,93/104 0,8} Ka3 {-99,94/112 0,7} 14. Nc4+ {+99,95/127 0,5} Ka2
{-99,98/127 0,1} 15. Nec3+ {+99,97/127 0,1} Ka1 {-99,98/1 0,1} 16. Nb3#
{+99,95/127 0,1}
{White mates} 1-0

@PersistentOne Yes, I believe from a reasonable starting position (i.e. none of the knights is lost by force), the knights should win. You just keep the knights and your king in a bunch, so that they all defend each other, avoiding nasty queen checks while driving the other king to the edge of the board. This will lead to mating threats, so the computer would give up the queen for one of the knights at some point. As @RapidVariants said, the four knights then win against the lone king. Even if two knights are lost for the queen, the remaining three knights are still winning.

Here is how I played against the computer from the position @Panagrellus provided:

@Schemato I think what RapidVariants meant was that 4knights win against the queen. I actually looked it up, and while not all positions are a win (already removing the ones where a knight is lost in the first move), most are. The lomonosov tablebase has all endgame positions with less than 7pieces on the board and the result for each one (with perfect play).
Im not sure if a mate-in-51+ can be considered a win though, (because of the draw at move50 rule).

@lp24 Thanks, you are right, I misread what @RapidVariants said. Of course sacrificing one knight just to reach a tablebase position is not a very practical approach, but then again the whole scenario is not very practical in the first place.

lichess.org/analysis/standard/8/8/3q4/3k4/8/1N1K1N2/8/3N1N2_w_-_-#0
reveals it's a win with 4 knights

[FEN "8/8/3q4/3k4/8/1N1K1N1N/8/3N1N2 w -"]

1. Nc3+ Kc6+ 2. Nbd4+ Kd7 3. Ne3 Qa6+ 4. Nc4 Qa1
5. Nhg5 Kd8 6. Nge6+ Ke8 7. Nd6+ Ke7 8. Nde4 Qa6+
9. Kc2 Qxe6 10. Nxe6 Kxe6 11. Kd3 Kf7 12. Nd4 Kg8
13. Nd5 Kf7 14. Kc3 Kg8 15. Ndf6+ Kf8 16. Kd3 Ke7
17. Kc4 Kd8 18. Kd5 Ke7 19. Ke5 Kf7 20. Nd6+ Kg6
21. Nf3 Kg7 22. Nh4 Kh6 23. Nf7+ Kg7 24. Ke6 Kf8
25. Nd6 Kg7 26. Ndf5+ Kh8 27. Ng6#