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Math Question

I asked my dad to explain this to me and I listned being like: yeah obiously I knew that all along, while I am thinking (what the...)
@CosmicPegasus2006 said in #10:
> @natbee56 , I am not a maths genius so I can be wrong but is the number 53,54,55... to 67 for the value of B. That's there should be 15 values for B
not quite
A+52=B
C+70=D
If C=2A, A>0 and B+D<200/ the question is actually A-B=-52 and 2A-D=-70 it said that A should be more than 0 it means 1,2,3...so now B is 53 and D 72 B+C= 125 now i know that B can start with 53 okay and after that i understand ____A<30 and i tried other numbers and finally solve that . I wrote it in my paper so I don't know if you can get it or not .A is 26 so B is 78 and C= 122 llll 26-78=-52 ,52-122=-70 /122+78 =200 it's exactly 200 so it can't be the correct answer after that i tried to do it with 25 so B now is 77 and C 120 B+C(77+120=197) so B can be 53,54,55.....77
As long as 0.1 ≤ B ≤ 77.99999999 it's true right?
<Comment deleted by user>
The answer is 25
We use algebra.
A+52=B Is also the same as
A=B-52
so we multiply by 2
2A=C
C=2B-104
We can write as
2B-104+70=D
Which equals to
2B-34=D
So we use guess-and-check
The smallest value is 53 since A cannot be 0 or less
If you guess correctly, the largest value is 77
77-53+1=25(Ans)
@natbee56 said in #1:
> A+52=B
> C+70=D
> If C=2A, A>0 and B+D<200
> Find the number of possible values for B
> Show us your working.
Bee

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