Lets say that we have a position, in which black only has a king and bishop and white has only a king and some number of bishops greater than 1. All of whites bishops are on the same color squares. White has his/her king in the center of the board, but black can force white into checkmate using his/her king and bishop.
Can you figure out the number of bishops white has? There is only one answer that works.
guessing 32
Cook.
Your question: "Can you figure out the number of bishops white has?"
My answer: "Yes"
I Guess 7
You wasted my time trying to solve this problem.It is impossible.
There is no "centre "of the board on which any piece can stand at one time.
Lots of superfluous information given.
Not enough pertinent information given.
I'm guessing you never tried to solve a trinomial equation given only two unknowns.
@bunyip yeah but he says that you black can ‘force a checkmate’ meaning it has to be 32, since a dark square bishop would be able to mate white then.
You can't have 32 of any piece..the max is 9 excluding the king of course.That is,if he means promoted pieces or just any random number that has zero to do with the constraints of the rules of chess.
@bunyip yeah that's what i believed he meant. He should have used more detail on his "Riddle" tho.