Did you ever hear of "binomial" formulas or "binomial expansions" (i think it is called this way in English). It is quite easy: (a + b)^^x = a^^x + i[1]a^^(x-1)b + i[2]a^^(x-2)b^^2 + ... i[n-2]

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cube or cuboid? For cube, a=b=c=18. Followup question, is there any solution for a cuboid that is not a cube (i.e. not all three a,b,c are equal).

AREA(cube)=VOLUME(cube) <=> 6 (ab+bc+ca) = abc with a solution in N. gl.

(a+b)^10

A Challenge for yourself*krasnaya *

> Find a way to prove that this is in fact divergent. Take 1/2 and it is clearly equal or greater than 1/2. Then take the next 2 terms, 1/3+1/4. Since 1/3 is bigger than 1/4 it is again equal or gr

A Challenge for yourself*NoobBatter *

It's 1/n, 1/n+1, 1/n+2... so it should keep on going on forever because the denominator is all the natural numbers... idk ;o

A Challenge for yourself*CovalentCompounds *

The series known as the harmonic series is divergent, meaning it tends off to infinity, 1 + 1/2 + 1/3 + 1/4 + 1/5 +....... Find a way to prove that this is in fact divergent.

A Challenge for yourself*CovalentCompounds *

The series known as the harmonic series is divergent, meaning it tends off to infinity, 1 + 1/2 + 1/3 + 1/4 + 1/5 +....... Find a way to prove that this is in fact divergent.

It's a good idea to expand it out that way, when I was thinking it in my head some how I got eight x four = 24; in that case, the width would be 256/ 24 = 10 2/3. Checking my work, I'd get 10.666

V=WxLxH 256=Wx4x8 256=Wx32 256/32=W 8=W I hope not bother with the development, I like to work in this way when I solve exercises, no matter how "easy" they are