Free online Chess server. Play Chess now in a clean interface. No registration, no ads, no plugin required. Play Chess with the computer, friends or random opponents.
Create a game Tournament Simultaneous exhibitions
Chess basics Puzzles Practice Coordinates Study Coaches
Lichess TV Current games Streamers Broadcasts (beta) Video library
Players Teams Forum Questions & Answers
Analysis board Opening explorer Board editor Import game Advanced search
Sign in
1,413 members

That's Mathematics!!!! TEAM

This team is for people who love math, math jokes, math concepts and applications, and cool stuff like that.
Location: within the R of any Nth dimentional space

Forum (456)

  1. Hard Math henryliu2009

    i don't know. I'm only 9 years old.

  2. Hard Math BOT centaur01

    @MoistvonLipwig Or yes, just look at all possible cases in mod 24. :) I like also this variation: Not divisible by 2 and by 3 means p = 6p' +/- 1 and q = 6q' +/- 1. Then p^2 - q^2 = 36p'^2 + 36

  3. Hard Math BOT centaur01

    Doh, i'm dumb. It can be done in more simple way. a) For any prime p, p ≡ 1 or p ≡ 3 or p ≡ 5 or p ≡ 7 (mod 8), therefore p^2 ≡ 1 (mod 8). b) The same thing for p^2 ≡ 1 (mod 3), as previously. c

  4. Hard Math MoistvonLipwig

    This proof isn't exactly pretty but it works so whatever. :D Clearly every prime number greater than 3 is either +1 or -1 mod 6. So the possible mod 24 values are +- (1, 5, 7, 11). Then simply square

  5. Hard Math BOT centaur01

    The same thing for any numbers p and q that are no divisible by 2 or 3 (not necessarily primes).

  6. Hard Math BOT centaur01

    Let's p = 2*p' + 1 and q = 2*q' + 1 (as they both are odd) Then p^2 - q^2 = (p+q)(p-q) = (2*p'+2*q'+2)*(2*p'-2*q') = =4*(p'+q'+1)*(p'-q'). Either p'-q' is even, or p'+q'+1 is even - therefore p^2-

  7. Hard Math mathpluschess

    Here's a problem: Let p and q be primes greater than 3. Prove that p^2 - q^2 is divisible by 24. good luck!

  8. I have youtube channel called antichess nikhil2609

    Please everyone subscribe it

  9. The Antelope Graph (Modified Knight) MrCharles

    I was doing a small bit of research on a number sequence that popped-out at me in the course of my work. Specifically, a modified (x, y) graph (grid). That research is a bit complex to explain, but, i

  10. MindYourDecisions YT channel Classicler

    Mathematician Presh Talwalkar tackles some tricky math problems from around the world, particularly in Asia. Math problems include this:

That's Mathematics!!!! Forum »