I understand that in a position where no mate is possible for black, if white's time runs out, the game should be counted as a draw. I just tried what happens if there is enough material in principle, but the pawn chains are sufficiently interlocked such that no piece can cross to the opponents side.
a) am I correct that this should be a draw?
b) if so, is there a good explanation for why it is hard for the computer to be sure that there is no possible mate for white in such positions?
a) am I correct that this should be a draw?
b) if so, is there a good explanation for why it is hard for the computer to be sure that there is no possible mate for white in such positions?