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A more politically correct way of identifying your pieces.

@bunyip: My spare time is not infinite; I have built a time travelling machine, but it only goes 5 minutes back in time (the instructions from ikea told me to use a Delorean, but all I could afford was a Peugeot). It is near infinite, but eventually, my battery money will run out.

Also, while we are on the subject, the last 10 capchas I have had have all been Fool's Mate (needs a more politically correct designation, by the way). I think my computer is mocking me.
@clousems
You really should have followed the Ikea instructions and made the financial sacrifice to obtain a Delorean...in comparison,Peugeots are crap.
Also,as with all Ikea stuff,you would have ended up with at the very least one Delorean bit left over.
Surely you can see that by only ever going back in time you are continuously regressing to an era of inferior battery technology,so of course your battery usage is going down the S-bend.
@bunyip:
you are overlooking one important advantage of the peugeot: I can extort money from local businesses by threatening to park in their parking lots.
Not Delorean money, mind you, but enough to afford new batteries.
Time travel is not possible as we do not know the speed at which we are travelling through space of in which direction. Hm... somewhat like a Peugeot driver.
Cancel the above first sentence.
Well, at least it wasn't a Renault
E=m(crap car)^2
Einstein's theory of Renault Activity
I'm not sure why we seem to be critisizing cars made by the cheese eating surrender monkeys.

Anyway E does not = Mc2 It is a bit more complicated than that. Look up Lorentz transformation equations
The most common form of the transformation, parametrized by the real constant {\displaystyle v,} v, representing a velocity confined to the x-direction, is expressed as[1]

{\displaystyle {\begin{aligned}t'&=\gamma \left(t-{\frac {vx}{c^{2}}}\right)\\x'&=\gamma \left(x-vt\right)\\y'&=y\\z'&=z\end{aligned}}} {\displaystyle {\begin{aligned}t'&=\gamma \left(t-{\frac {vx}{c^{2}}}\right)\\x'&=\gamma \left(x-vt\right)\\y'&=y\\z'&=z\end{aligned}}}
where (t, x, y, z) and (t′, x′, y′, z′) are the coordinates of an event in two frames, where the primed frame is seen from the unprimed frame as moving with speed v along the x-axis, c is the speed of light, and {\displaystyle \gamma =\textstyle \left({\sqrt {1-{\frac {v^{2}}{c^{2}}}}}\right)^{-1}} {\displaystyle \gamma =\textstyle \left({\sqrt {1-{\frac {v^{2}}{c^{2}}}}}\right)^{-1}} is the Lorentz factor. When speed v is significantly lower than c, the factor is negligible, but as v approaches c, there is a significant effect. The value of v cannot exceed c, in current understanding.

Expressing the speed as {\displaystyle \beta ={\frac {v}{c}},} {\displaystyle \beta ={\frac {v}{c}},} an equivalent form of the transformation is[2]

{\displaystyle {\begin{aligned}ct'&=\gamma \left(ct-\beta x\right)\\x'&=\gamma \left(x-\beta ct\right)\\y'&=y\\z'&=z.\end{aligned}}} {\displaystyle {\begin{aligned}ct'&=\gamma \left(ct-\beta x\right)\\x'&=\gamma \left(x-\beta ct\right)\\y'&=y\\z'&=z.\end{aligned}}}
I was quoting Einstein. He was German, so presumably, he owned a Subaru. And, like most Germans between 1870 and 1945, he hated French cars. I was not issuing a statement as to the validity of the theory of Renault activity, as I have no idea how real math works -- been dealing with statistics for too long.
Also, velocity and speed are not identical. Remember, Velocity starts with a V, so it's a Vector (I knew that physics class freshman year would be useful)
@clousems

"There are lies..there are damned lies..then there are statistics".
Can't recall who said that..someone famous.

In 1994 Renault and a Peugeot challenged each other to a standing-start quarter mile...officials estimate at least one of them should cross the finish line on or about New Years Day 2020.
Lada drivers have been trolling the racers by doing circles around them...in reverse.Updates as they come to hand.

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