@obladie said in #10:
> Nah...yr struggling...
What is this, the 60s. Just to bring you up to date, the modern abbreviation for you are is ur rather than yr.
I'm guessing that for you, "modern" means anything post-2020.
@TakeThePawnOrLose If any one of the answer is correct than the probability of me getting it correct is 1/4.
I don’t like the options to choose from.
Seems to me that by introducing a weighted probability it has become a causality problem on top of a math problem, so I’ll have to ask my nephew who turned eleven a few days ago.
@TakeThePawnOrLose said in #1:
> If you randomly select one of the options listed below, what is the probability of you getting it correct?
> a) 25%
> b) 50%
> c) 0%
> d) 25%
1/3...very very easy
<Comment deleted by user>
I believe it's 0%, the probability, very good question!
The probability of a correct answer, chosen randomly, is 1 out of 4, so it's 25%, but 25% is the answer of 'a' and 'd', so the probabilities of getting the correct answer are doubled (50%).
It would be letter 'b', 50%, but since the correct answers are 'a' and 'd', and it's incorrect to select them, because it's now 50%, it's not possible to select the correct answer. So, the answer becomes 0%, letter 'c'.
@celinofj you have 25% chance of selecting c). So if the correct answer was 0, then the probability of being correct would be 25%...
