lichess.org
Donate

Magnus vs Lichess??

Hello to everyone
yesterday i was reading a chess book called Kaspaov vs Rest of World and i've had a creazy idea. In fact, for those who did not know, in 1999 Kasparov played an interesting match against all of the world but this match had a particular oragnization: everyone could vote a move and the one that was most votated was played.
I think that with the means of Lichess there could be somethng like the Kasparov match: a corrispondence match between lichess members and a champion (maybe Magnus).
It's only an idea but I think that it could be possible.
Thanks for reading
L.M.

Sorry for my bad english.
This is common at chess.com.Thousands of common players against a master (IM or GM).
In spite of engines and computers , the amateurs often lose. They make all sorts of blunders! Very often , a stupid move is proposed and all the 1200s vote for it without thinking!!
In the pre-engine era there were many of these GM vs. everybody matches. (Karpov, Kasparov, Timman etc.etc.)
Almost all games ended in a draw because the average move will never be a brilliancy but also never a blunder.
Maybe this would be even better if all players vote on lines (with computer analysis) instead of single moves. The titled players of lichess then vote on the 5 lines that got the most votes by all members of lichess and the first move of the line that gets the most votes by the titled players gets played. Magnus should also be allowed to use engines and other support. Half of the games are normal games and in half of the games a draw counts as a win for black (so white will take more risks).
If Magnus would really agree to what is discussed here, it would make news worldwide, I'm sure of it.
I think it's too late for something like this. The move chosen will basically only be differing computer moves, so it would basically be Magnus vs Lichess's engines
How much will the champion be paid?
He would not play those computer's (competitors) for free.

This topic has been archived and can no longer be replied to.