Hey folks- here's a puzzle I just created recently:
The goal is to reach the position below in exactly EIGHT moves, with it being white to move by the time this exact position is on the board.
It's not a very difficult puzzle, but it's interesting. Here's the position:
Two white bishops on white squares? Really?
A clandestine reverie; discreetly reticulated and scrupulously composed. The crux occurs on move 4.
Good one!
How can you get the dark squared bishop into the light squares without moving the pawns blocking the dark squared bishop?
How do you do it in 4 moves?
So far, I have 1. Nf3 Nc6 2. Ne5 Nxe5 3. g3 Nc6 4. Bg2 Nb8
It's impossible : all the white pawns are on board, so there have been no promotion. So having two light square bishops is not possible.
The challenge is impossible for the following reasons:
1) A bishop can't move to a square so that the square it is currently on is not the same color as the square it moves to, as the checkerboard color pattern has the same colors on it's diagonals. The only way that is possible is to have promoted a pawn.
2) All the pawns are on the board, so that means no pawn-promotion happened.
I solved it as well. Though there are multiple solutions which make it easy but you said it's not a difficult puzzle so it's good.
My left leg is slightly shorter than my right leg. I compensate for this by wearing a bright blue beret.
Maybe OP does not know the difference between knight and bishop and in what position they start!? -anyway it is not possible to guess what is meant.
It's an impossible position assuming it were regular chess.
If it were crazyhouse I believe it could be done if black wins whites dark bishop with his knight, then gives the bishop back for free.