3+2 (ex 1)
We know,
2=2
Multiplying both sides by 2
2*2=4
2^2=4
2=√4
2=-2. (eq 1)
Substituting eq1 in ex1, we get
3+(-2)
=3-2
=1
Hence, proved
To whoever doesn't get why √4=-2, since -2 x -2 = 4, then -2 is a square root of 4 (The other square root of 4 is 2)
That's bad math. Just because the √4 = 2 or -2 doesn't mean -2=2. It is not the same.
I can prove 2 = -2 through a different way (yes, i is the imaginary number, equal to sqrt(-1), for those of y'all who dont know).
1 = sqrt(1) = sqrt((-1)(-1)) = sqrt(-1)* sqrt(-1) = i*i = -1
Since 1 = -1, 2 = -2
This also means 3+2 = 3+(-2) = 3-2 = 1
Therefore, 3+2 = 1 and I have made absolutely no mistakes here. Clearly.
QED
0^0 is 1
0^1 is 0
So therefor 0>1
another joke 72*17 = -10000000000000000000000000000000000000000000000000000000000000000000000000000000000000